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1.20 gm sample of NaCO(3) " and " K(2)CO...

`1.20` gm sample of `NaCO_(3) " and " K_(2)CO_(3)` was dissolved in water to form 100 ml of a Solution : 20 ml of this solution required 40 ml of `0.1` N HCl for complete neutralization .
Calculate the weight of `Na_(2)CO_(3)` in the mixture. If another 20 ml of this solution is treated with excess of `BaCl_(2)` what will be the weight of the precipitate ?

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To solve the problem step by step, we will break it down into two parts: the calculation of the weight of \( \text{Na}_2\text{CO}_3 \) in the mixture and the calculation of the weight of the precipitate formed when the solution is treated with excess \( \text{BaCl}_2 \). ### Step 1: Define Variables Let: - \( x \) = weight of \( \text{Na}_2\text{CO}_3 \) in grams - \( y \) = weight of \( \text{K}_2\text{CO}_3 \) in grams From the problem, we know: ...
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