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In basic solution CrO4^(2-) oxidises S2O...

In basic solution `CrO_4^(2-)` oxidises `S_2O_3^(2-)` to form `[Cr(OH)_4]^(ɵ)` and `SO_4^(2-)` How many millilitres of 0.154 `M Na_2CrO_4` are required to react with 40.0 " mL of " 0.246 M `Na_2S_2O_3`.

A

`200 ml `

B

`156.4 ml`

C

`170.4 ml`

D

`190.4 ml`

Text Solution

Verified by Experts

The correct Answer is:
C
`40 xx 0.246 xx 8 = V xx 0.154 xx 3 ("Meq. of " S_(2)O_(3)^(2-) = " Meq. of " CrO_(4)^(2-))`
`:. V = 170.4 ml`
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