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20mL of 0.2M Al(2)(SO(4))(3) is mixed wi...

20mL of 0.2M `Al_(2)(SO_(4))_(3)` is mixed with 20mL of 0.6M `Bacl_(2)`.Concentration of `Al^(3+)`ion in the solution will be:

A

`0.2 M`

B

`10.3 ` M

C

`0.1 M`

D

`0.25` M

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(" "Al_(2)(SO_(4))_(3) " "+ BaCl_(2) " "to BaSO_(4) downarrow + AlCl_(3)),("Initial Meq. "20 xx 0.2 xx 6 " "20 xx 0.6 xx 2 " 0 0"),(" "=24" "=24),("Final Meq. "0" 0 24 24"):}`
`[Al^(3+)] = 24/(40 xx 3) = 0.2 M`
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