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NalO(3) reacts with NaHSO(3) according t...

`NalO_(3)` reacts with `NaHSO_(3)` according to eaquation `Io_(3)^(-)+3HSO_(3)^(-)to I^(-)+3H^(+)3SO_(4)^(2-)`The weight of `NaHSO_(3)` required to react with 100 mL of solution containing 0.58 gm of is :

A

`5.2` gm

B

`4.57` gm

C

`2.3 ` gm

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B
`W_(NaHSO_(3))/M_(NaHSO_(3)) xx 2 xx 1000 = (0.58)/198 xx 6 xx 100`
`W_(NaHSO_(3)) = (0.58 xx 6 xx 1000 xx 104)/(198 xx 1000) = 4.57`
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