Home
Class 12
CHEMISTRY
The number of moles of KMnO(4) that will...

The number of moles of `KMnO_(4)` that will be required to react with one mol of ferrous oxalate is :

A

`3/5`

B

`2/5`

C

`4/5`

D

1

Text Solution

Verified by Experts

The correct Answer is:
A

`Mn^(7+) + 5e^(-) to Mn^(2+) ] xx 3`
`{:(Fe^(2+) to Fe^(3+) + e^(-)),(C_(2)O_(4)^(2-) to 2CO_(2) + 2e^(-)):}]xx 5 `
3 moles of `KMnO_(4) = 5 " moles of " FeC_(2)O_(4)`
` :. ` 1 mol of forrous oxalate ` -= 3/5" mol of " KMnO_(4)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of moles of KMnO_(4) that will be needed to react completely with one mole of ferrous oxalate in acidic solution is:

The number of moles of KMnO_(4) that will be needed to react completely with one mole of ferrous oxalate in acidic solution is:

KMnO_(4) acts as an oxidising agent in acidic medium. The number of moles of KMnO_(4) that will be needed to react with one mole of sulphide ions in acidic solution is

KMnO_(4) acts as an oxidising agent in acidic medium. The number of moles of KMnO_(4) that will be needed to react with one mole of sulphide ions in acidic solution is

KMnO_(4) acts as an oxidising agent in acidic medium. The number of moles of KMnO_(4) that will be needed to react with one mole of sulphide ions in acidic solution is

The number of moles of KMnO_(4) that will be needed to react with one mole of sulphite ion in acidic solution is

How many moles of KMnO_(4) will be needed to react completely with one mole of ferrous oxalate (FeC_(2)O_(4)) in acidic solution?

The number of moles of HIO_(4) required in the above reaction is:

The number of moles of HIO_(4) required in the above reaction is:

Number of moles of MnO_(4)^(-) required to oxidise one mole of ferrous oxalate completely in acidic medium will be