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The volume of 3M HNO(3) required to oxi...

The volume of 3M `HNO_(3)` required to oxidised 8 g `Fe^(2+)` is
`(HNO_(3) + Fe^(2+) to Fe^(3+) + NO + H_(2)O)`

A

`8 `ml

B

`16 ml`

C

`32 ml`

D

`64 ml `

Text Solution

Verified by Experts

Meq. of `HNO_(3) = " Meq. of " Fe^(2+)`
or `3 xx 3 xx V = 8/56 xx 1000`
` V = 15.87` ml
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