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The minimum quantity of needed to prec...

The minimum quantity of needed to precipitate 64.5 gm of `Cu^(2+)` will be nearly :

A

`63.5` gm

B

`31.75` gm

C

`34` gm

D

`2.0` gm

Text Solution

Verified by Experts

The correct Answer is:
C
Meq. of `H_(2)S = " Meq. of " Cu^(2+)`
`:. W_(H_(2)S)/(34//2) xx 1000 = (63.5)/(63.5//2) xx 1000`
` :. W_(H_(2)S) = 34 ` gm
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