10 g of `CaCO_(3)` contains :

1000 gram aqueous solution of CaCO_(3) contains 10 gram of carbonate. Concentration of solution is:

10.0 g of CaCO_(3) on heating gave 4.4 g of CO_(2) and x g of CaO. Applying law of conservation of mass calculate the mass of CaO.

10.0 g of CaCO_(3) on heating gave 4.4 g of CO_(2) and x g of CaO. Applying law of conservation of mass calculate the mass of CaO.

An impure sample of CaCO_(3) contains 38% of Ca. The percentage of impurity present in the sample is :

1000 gram aqueous solution of CaCO_(3) contains 20 gram of carbonate. Concentration of solution is:

In an experiment 5.0 g of CaCO_(3) on heating gave 2.8 g of CaO and 2.2 g of CO_(2) . Show that these results are in accordance to the law of conservation of mass.

A pure sample of CaCO_(3) contain 100 moles of total atoms. What is the mass of sample-

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=1365g mol^(-1) )

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=136 gmol^(-1) )

10 grams of CaCO_(3) is completely decomposed to x and CaO. 'x' is passed into an aqueous solution containing 0.1 mole of sodium carbonate. What is the number of moles of sodium bicarbonate formed? (mol. wts: CaCO_(3) = 100, NaCO_(3) = 106, NaHCO_(3) = 84 )