In a reaction vessel `0.184 g` of `NaOH` is required to be added for completing the reaction. How many millilitre of `0.150M NaOH` solution should be added for this requirements?

Answer

To solve the problem of how many milliliters of a 0.150 M NaOH solution are needed to provide 0.184 g of NaOH, we can follow these steps:

### Step 1: Calculate the number of moles of NaOH required.
To find the number of moles, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
The molar mass of NaOH is approximately 40 g/mol.

\[ \text{Number of moles of NaOH} = \frac{0.184 \, \text{g}}{40 \, \text{g/mol}} = 0.0046 \, \text{mol} \]

### Step 2: Use the molarity to find the volume of the solution needed.
Molarity (M) is defined as the number of moles of solute per liter of solution. Therefore, we can rearrange the formula for molarity to find the volume:
\[ \text{Molarity (M)} = \frac{\text{Number of moles}}{\text{Volume (L)}} \]
Rearranging gives:
\[ \text{Volume (L)} = \frac{\text{Number of moles}}{\text{Molarity (M)}} \]

Substituting the values we have:
\[ \text{Volume (L)} = \frac{0.0046 \, \text{mol}}{0.150 \, \text{M}} = 0.03067 \, \text{L} \]

### Step 3: Convert the volume from liters to milliliters.
Since 1 L = 1000 mL, we convert:
\[ \text{Volume (mL)} = 0.03067 \, \text{L} \times 1000 \, \text{mL/L} = 30.67 \, \text{mL} \]

### Final Answer:
You need to add approximately **30.67 mL** of the 0.150 M NaOH solution to provide 0.184 g of NaOH.

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