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CuSO(4)+2KI to CuI darr+(1)/(2)I(2)+K(2)...

`CuSO_(4)+2KI to CuI darr+(1)/(2)I_(2)+K_(2)SO_(4)`

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`40 `ml
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2KI+CuSO_(4) to CuI darr+(1)/(2)I_(2)+K_(2)SO_(4)

CuSO_(4)+2KCN to CuCN darr+(CN)_(2)uarr+K_(2)SO_(4)

CuSO_(4)+2KCN to CuCN darr+(CN)_(2)uarr+K_(2)SO_(4)

In the reaction 2CuSO_(4)+4KI rarr 2Cu_(2)I_(2)+I_(2)+2K_(2)SO_(4) the equivalent weight of CuSO_(4) will be:

Cu^(2+)(aq)+2I^(-) to CuI darr+(1)/(2)I_(2)

In iodometric titrations, an oxidizing agent such as KNnO_(4), K_(2)Cr_(2)O_(7),CuSO_(4),H_(2)O_(2) is allowed to react in neutral medium or in acidic medium with excess of potassium iodide to liberate free iodine Kl+ oxidizon agent to l_(2) Free iodine is titrated against stanard reducing agent usually with sodium thiosulphate i.e., K_(2)Cr_(2)O_(7)+6Kl+7H_(2)SO_(4)toCr_(2)(SO_(4))_(3)+4K_(2)SO_(4)+7H_(2)O+l_(2) 2CuSO_(4)+4Kl to Cu_(2)l_(2)+2K_(2)SO_(4)+l_(2) l_(2)+Na_(2)S_(2)O_(3)to 2Nal+Na_(2)S_(4)O_(6) In iodometric titrations, starch solution is used as an indicator. Starch solution gives blue or violet colour with free iodine. At the end point, blue or violet colour disappear when iodine is completely changed to iodide. What volume of 0.40M Na_(2)S_(2)O_(3) would be required to reach with l_(2) liberated by adding 0.04 mole of Kl to 50 mL to 0.20 M CuSO_(4) solution?

Iodine titration can be iodemotric or iodimetric depending on using iodine directly or indirectly is an oxidising agent in the redox titration. a. Iodimetric titration in which a standard iodine solution is used as an oxidant and iodine is directly or indirectly titrated against a reducing agent. For example. 2CuSO_(4)+4KJtoCu_(2)I_(2)+2K_(2)SO_(4)+I_(2) b. Iodimetric procedures are used for the datermination of strength of reducing agent such as thiosulphates, sulphites, arsenties adn stanous chloride etc. by titrating them against standard solution of iodine in a burette. 2Na_(2)SO_(3)to2 NaI +Na_(2)S_(4)O_(6) Starch is used as indicator near the end point whilch form blue colour complex with I_(3)^(-) . The blue colour disappeams when there is not more of free I_(2) . The volume of KI solutioin used for CuSO_(4) will be

H_(3)PO_(2)+CuSO_(4) to Cu darr+H_(3)PO_(4)+HNO_(3)

In the reaction Cu+ underset((Conc.))(H_(2)SO_(4))to CuSO_(4) +SO_(2) +H_(2)O H_(2)SO_(4) behaves w.r.t. Cu as

K_(4)[Fe(CN)_(6)]+2CuSO_(4)toCu_(2)[Fe(CN)_(6)]darr+2K_(2) SO_(4)