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27.6 g K(2)CO(3) was treated by a series...

27.6 g `K_(2)CO_(3)` was treated by a series of reagents so as to convert all of its carbon to `K_(2)Zn_(3)[Fe(CN)_(6)]_(2)` . Calculate the weight of the product. [mol. Wt. of `K_(2)CO_(3)` =138 and mol. Wt. of `K_(2)Zn_(3)[Fe(CN)_(6)]_(2)=698]`

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The correct Answer is:
`11.6 `g
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27.6gK_(2)CO_(3) was treated by a series of reagents so as to convent all of its carbon to K_(2)Zn_(3)[Fe(CN)_(6)]_(2) Calculate the weight of the product [mol.wt. of K_(2)CO_(3)=138 and mol. Wt. of K_(2)Zn_(3)[Fe(CN)_(6)]_(2)=698] .

27.6gK_(2)CO_(3) was treated by a series of reagents so as to convent all of its carbon to K_(2)Zn_(3)[Fe(CN)_(6)]_(2) Calculate the weight of the product [mol.wt. of K_(2)CO_(3)=138 and mol. Wt. of K_(2)Zn_(3)[Fe(CN)_(6)]_(2)=698] .

In the complex K_(2)Fe[Fe(CN)_(6)] :

The spin magnetic moment of iron in K_(3)[Fe(CN)_(6)]

Write IUPAC name of K_3[Fe(CN)_6]

In the complex K_2Fe[Fe(CN)_6]

Why K _(3)[Fe(CN)_(6)] is more stable than K_(4)[Fe(CN)_(6)]

3KCN+Fe(CN)_(3)darr to K_(3)[Fe(CN)_(6)]

Effective atomic number of Fe in the complex K_(3)[Fe(CN)_(6)] is

Fe(CN)_(2)darr+KCN to K_(3)Fe(CN)_(6)