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0.58 g of CH3(CH2)(c)COOH was burnt in e...

0.58 g of `CH_3(CH_2)_(c)COOH` was burnt in excess air and the resulting gases `(CO_2` and `H_2O`) were passed through excess NaOH solution. The resulting solution was divided into two equal parts. One part requires 50 " mL of " 1.0 M HCl for complete neutralisation using phenolphthalein indicator. Another part required 80 " mL of " same HCl for neutralisation using methyl orange as indicator. Calculate the value of n and the amount of excess NaOH solution taken initially.

A

`2.5 xx 10^(-2)`

B

`5 xx 10^(-2)`

C

`10xx10^(-2)`

D

`1.5 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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