Calculate the energy associated with the 2nd orbit of `Be^(3+)`. Also calculate the radius. For `Be^(3+),Z=4,n=2`

Explanation

To solve the problem of calculating the energy associated with the 2nd orbit of \( \text{Be}^{3+} \) and the radius of that orbit, we will use the following formulas:

1. Energy of an electron in orbit:
\[ E = -\frac{13.6 Z^2}{n^2} \text{ eV} \]

2. Radius of the orbit:
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