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Show that the circumference of the Bohr ...

Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit

Text Solution

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According to de Broglie.
`lamda=h/("mu")`……….i
Also mur `=(nh)/(2pi)`…….ii
By eqs (i) and (ii) `lamda=(h.2pir)/(n.h)`
or `2pir=n lamda`
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