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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H-atom is `-13.6eV.` The possible energy value of the excited state for electrons in Bohr orbits of hydrogen is :

A

`-3.4eV`

B

`-4.2eV`

C

`6.8eV`

D

`+6.8eV`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(n)=(-13.6)/(n^(2))eV`
When `n=2, E_(2)=(-13.6)/4=-3.4eV`
Hence A is the correct answer.
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