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When an electron in an excited state of ...

When an electron in an excited state of Mo atoms falls from L to K-shell , an X-ray is emitted. These X-rays are diffracted at angle of `7.75^(@)` by planes with a separation of `2.94 Ã…`. What is the difference in energy between k-shell and L-shell in Mo, assuming of first order diffraction ? ( `sin 7.75^(@)=0.1349`)

Text Solution

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`2d sin theta = n lambda`
`1xx lambda = 2d sin theta = 2xx6.64xx10^(-10)xx sin (7.75)`
`therefore lambda = 7.123xx10^(-11)m`
`E=(hc)/(lambda)=(6.62xx10^(-34)xx3xx10^(8))/(7.123xx10^(-11))`
`= 27.88xx10^(-16)J`
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