Home
Class 12
CHEMISTRY
CsBr has bcc type structure with edge le...

CsBr has bcc type structure with edge length 4.3pm. The shorest inter ionic distance in between `Cs^(+) and Br^(-)` is:

A

`0.897 Å`

B

`3.72 Å`

C

`1.749 Å`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
B
For bcc structure
`2(r^(+)+r^(-))=sqrt(3)a`
or `2(r^(+)+r^(-))=sqrt(3)xx4.3`
or `(r^(+)+r^(-))=sqrt(3)xx(4.3)/(2)=3.72 Å`
Hence, the distance between `Cs^(+)` and `Br^(-)` ions will be `3.72 Å`
Hence, (B) is the correct answer.
Promotional Banner

Similar Questions

Explore conceptually related problems

CsBr has bcc like structures with edge length 4.3Å . The shortest inter ionic distance in between Cs^(+) and Br^(-) is:

CsBr has bcc stucture with edge length 4.3 A .The shortest interionic distance in between Cs and Br is

CsBr has bcc lattice with the edge length 9.4 Å, the shortest inter- ionic distance in between Cs^(+) & Br^(-) is:

CsBr has bcc structure with edge length of 43 pm . The shortest interionic distance between cation and anion is

A solid AB has NaCl type structure with edge length 580.4 pm. Then radius of A^(+) is 100 p m. What is the radius of B^(-) in pm?

CsCl has bc c arrangement and its unit cell edge length is 400 pm. Calculate the interionic distance in CsCl .

CsCl has cubic structure. Its density is 3.99 g cm^(-3) . What is the distance between Cs^(o+) and Cl^(Θ) ions? (Atomic mass of Cs = 133 )

CsCl has bec arrangement and its unit cell edge length is 400 pm. Calculate the inter-ionic distance in CsCl.

In a CsCl structure, if edge length is a, then distance between one Cs atom and one Cl atoms is

KF has NaCl type of structure. The edge length of its unit cell has been found to be 537.6 pm. The distance between K^(+)F^(-) in KF is