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Solution of a monobasic acid has a pH=5....

Solution of a monobasic acid has a pH=5. If one mL of it is diluted to 1 litre, what will be the pH of the resulting solution ?

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[ HCl] `= 10^(-5) M ` ( As pH = 5)
Meg . Of HCl in 1 ml = `10^(-5) xx 1 = 10^(-5)`
Let , normality after diluting
one ml of HCl ( pH = 5 ) to one L is (N)
Meg . Q of HCl (conc) = Meg. Of HCl (dilute )
`10^(5) xx1 = N xx 100 rArr N_(HCl(dil))= 10^(-8)`
`{:(HCl,to,H^(+),+,Cl^(-),),(10^(-8),,0,,0,"Intial"),(0,,10^(-8),,10^(-8),"Final"):}`
` :. [ H^(+)] = 10^(-8) ` but pH = 8 is not possible because it is acid , As `[H^(+)] = 10^(-7)` M are already present in solution and since `10^(-8) lt 10^(-7)` . Thus , it should not be neglected .
` :. [H^(+)] = 10^(-8) + 10^(-7) = (1.1) xx10^(-7) M ` (approximately ) .
` :. pH = 6.9586`
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