The acid ionization constant for
`Zn^(2+)+H_(2)O hArr (OH^(+)) + H^(+)`
is `1.0 xx 10^(-9) ` .Calculate the pH of `0.0010` M solution of `ZnCl_(2)` . Also calculate basic dissociation constant of `Zn(OH)^(+)`

Explanation

To solve the problem step by step, we will first calculate the pH of a 0.001 M solution of ZnCl₂ and then find the basic dissociation constant of Zn(OH)⁺.

### Step 1: Understanding the Ionization of Zn²⁺
The reaction given is:
\[ \text{Zn}^{2+} + \text{H}_2\text{O} \rightleftharpoons \text{Zn(OH)}^{+} + \text{H}^{+} \]
The acid ionization constant (Kₐ) for this reaction is provided as \( 1.0 \times 10^{-9} \).

### Step 2: Calculate Kb for Zn(OH)⁺
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