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What is the minimum volume of water requ...

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, `K_(sp)` is `9.1 xx 10^(-6)`).

Text Solution

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`CaSO_(4) (aq) hArr Ca^(2+)(aq) +SO_(4)^(2-) (aq)`
If S is the solubility of `CaSO_(4)` in moles `L^(-1)`
`K_(sp) = [Ca^(2+)] = [SO_(4)^(2-)] = S^(2)`
` :. S = sqrt(K_(sp)) = sqrt(9.1 xx10^(-6))`
` = 3.02 xx10^(-3) "ML"^(-1)` .
` = 3.02 xx10^(-3) xx136 "gmL"^(-1)`
` = 0.411 "gL"^(-1)`
For dissolving `1gCaSO_(4)` water required = `1/(0.41) L = 2.431 `
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