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Calculate the pH at which an acid indica...

Calculate the `pH` at which an acid indicator with `K_(a) = 1.0 xx 10^(-5)` changes colour when the indicator is `1.00 xx 10^(-3)M`.

Text Solution

Verified by Experts

For indicator dissociation equilibrium
`Hln hArr h^(+)+In^(-)`
Colour A Colour B
` K_(In) = ([H^(+)][In^(-)])/([Hln]) `
`rArr 1 xx 10^(-5) = ([H^(+)]xx 80//100)/(20//100)`
` :. [ H^(+)] = 0.25 xx 10^(-5)`
`:. pH = 5.6020 `
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