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The K(sp) of Mg(OH)(2) is 1xx10^(-12). A...

The `K_(sp)` of `Mg(OH)_(2)` is `1xx10^(-12)`. A 0.01 `"M MgCl"_(2)` solution will precipitate at what limiting pH value?

A

3

B

9

C

5

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
`[Mg^(2+)] [ OH^(-2)] ^(2) = 10^(-12)`
`0.01 xx [OH] = 10^(-12)`
`[OH] = 10^(-12)`
`[OH] = 10^(-5) M `
` [H^(+)] = 10^(-9) M ` and `pH = - log (10^(-9)) = 9 `
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