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The pH of a solution obtained by mixing ...

The pH of a solution obtained by mixing 100 ml of 0.2 M `CH_3COOH` with 100 ml of 0.2 N NaOH will be
`(pK_a "for " CH_3COOH=4.74 and log 2 =0.301)`

A

`4.74`

B

`8.87`

C

`9.10`

D

`8.57`

Text Solution

Verified by Experts

The correct Answer is:
B
Concentration of salt will be 0.1 M
`CH_(3) COOH + NaOH hArr CH_(3)COONa +H_(2)O`
`pH = 1/2 [pK_(w) +pK_(a) +log c ] `
` = 1/2 [ 14 + 4.74 -1 ] = 8.87`
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