An aqueous solution of aniline of concentration `0.24` M is prepared. What concentration of sodium hydroxide is needed in this solution so that anilinium ion concentration remains at `1xx10^(-8)M` ? `(K_(a)for C_(6)H_(5)NH_(3)^(+)=2.4xx10^(-5)M)`

Explanation

To solve the problem, we need to find the concentration of sodium hydroxide (NaOH) required to maintain the concentration of anilinium ions (C6H5NH3+) at \(1 \times 10^{-8} \, \text{M}\) in a solution of aniline (C6H5NH2) with a concentration of \(0.24 \, \text{M}\). The dissociation constant (\(K_a\)) for the anilinium ion is given as \(2.4 \times 10^{-5} \, \text{M}\).

### Step-by-Step Solution:

1. **Write the equilibrium expression for the dissociation of anilinium ion:**
\[ C_6H_5NH_3^+ \rightleftharpoons C_6H_5NH_2 + H^+ \]
...