Home
Class 12
CHEMISTRY
Calculate the change in pH of 1 litre bu...

Calculate the change in pH of 1 litre buffer solution containing `0.1` mole each of `NH_(3)` and `NH_(4)CI` upon addition of:
(i) `0.02` mole of dissolved gasous HCI.
Assume no change in volume. `K_(NH_(3))=1.8xx10^(-5)`

Text Solution

Verified by Experts

pH = `9.2553`
(a) Change in pH = `0.1761 ` unit , i.e ., pH decreases
(b) Change in pH = `0.1761 ` unit i.e ., pH increases
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the change in pH of 1 litre buffer solution containing 0.1 mole each of NH_(3) and NH_(4)CI upon addition of: (i) 0.02 mole of dissolved NaOH. Assume no change in volume. K_(NH_(3))=1.8xx10^(-5)

Calculate pH of the buffer solution containing 0.15 mole of NH_(4)OH " and " 0.25 mole of NH_(4)Cl. K_(b) " for " NH_(4)OH " is " 1.98 xx 10^(-5) .

Calculate pH of a buffer solution that contains 0.1M NH_(4)OH(K_(b)=10^(-5)) and 0.1 M NH_(4)Cl.

Calculate the pH of a buffer by mixing 0.15 mole of NH_(4)OH and 0.25 mole of NH_(4)Cl in a 1000mL solution K_(b) for NH_(4)OH = 2.0 xx 10^(-5)

To 1.0L solution containing 0.1mol each of NH_(3) and NH_(4)C1,0.05mol NaOH is added. The change in pH will be (pK_(a) for CH_(3)COOH = 4.74)

Calculate the pH of 0.5L of a 0.2 M NH_(4)Cl-0.2 M NH_(3) buffer before and after addition of (a) 0.05 mole of NaOH and (b) 0.05 mole of HCl . Assume that the volume remains constant.[Given: pK_(a) of NH_(3)=4.74]

Find the pH of a buffer solution having equal volumes of 0.2MNH_(4)OH and 0.2M NH_(4)Cl (K_(b) for base =1.0xx10^(-5) )

Calculate the pH of a solution made by mixing 0.1 M NH_(3) and 0.1M (NH_(4))_(2)SO_(4). (pK_(b) of NH_(3) = 4.76)

Calculate the pH of a buffer solution containing 0.15 mole of CH_3COOH and 0.1 mole of CH_3 COO Na per litre. The dissociation constant for acetic acid 1.8 xx 10 ^(-5)

A buffer solution contains 0.02 moles of NH_4OH and 0.03 moles of NH_4CI dissolved in 1 litre of the solution. Calculate the pH of the solution. Dissociation constant of NH_4OH "is" 1.8 xx 10^-5