In the reaction `I^(-) +I_(2) rarr I_(3)^(-)`, the Lewis acid is ……….. .

In the equation I_(2)+I^(-) rarr, I_(3)^(-) which is Lewis base

In the reaction SnCl_(4)+2Cl^(-)rarr[SnCl_(6)]^(2-) which is Lewis acid and which one is base?

For the reaction , Cl_(2)+2I^(-) rarr I_(2)+2Cl^(-) , the initial concentration of I^(-) was 0.20 "mol lit"^(-1) and the concentration after 20 minutes was 0.18 "mol lit"^(-1) . Then the rate of formation of I_(2) in "mol lit"^-1min^-1 would be

Find the current I_(1) , I_(2) , & I_(3) , in the circuit.

Calculate the euilibrium constant for the reaction, 2Fe^(3+) + 3I^(-) hArr 2Fe^(2+) + I_(3)^(-) . The standard reduction potential in acidic conditions are 0.77 V and 0.54 V respectivelu for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

I_(2)+KIrarrKI_(3) In the above reaction :-

Find the standard electrode potential of I_(2)|2I^(c-) if the equilibrium constant for the reaction I_(2)+I^(c-) rarr_'(I_3)^(c-) is 703. The standard electrode potential of I_(3)^(c-)|3I^(c-) is 0.5355V . Also give the electrode reaction.

In the reaction, I_(2)+2S_(2)O_(3)^(2-) rarr 2I^(-)+S_(4)O_(6)^(2-) .

For the reaction, 2HI(g) rarr H_(2)(g) + I_(2) (g) - Q KJ , the equilibrium constant depends upon

Rate constant for a reaction H_(2) + I_(2) rarr 2HI is 49 , then rate constant for reaction 2HI rarr H_(2) + I_(2) is