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0.16g of N(2)H(4) are dissolved in water...

`0.16`g of `N_(2)H_(4)` are dissolved in water and the total volume made upto 500 mL. Calculate the percentage of `N_(2)H_(4)` that has reacted with water in this solution. `(K_(b)` for `N_(2)H_(4)=4.0xx10^(-6))`

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(i) 1165 mg (ii) 2%
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