A solution of weak acid HA was titrated ...

A solution of weak acid HA was titrated with base NaOH. The equivalent point was reached when 40 mL. Of 0.1 M NaOH has been added. Now 20 mL of 0.1 M HCl were added to titrated solution, the pH was found to be 5.0 What will be the pH of the solution obtained by mixing 20 mL of 0.2 M NaOH and 20 mL of 0.2 M HA?

Verified by Experts

`1.2 xx 10^(-5)`

Similar Questions

Explore conceptually related problems

The pH of a solution obtained by mixing 50 mL of 0.4 N HCl and 50 mL of 0.2 N NaOH is

Calculate the pH of solution obtained by mixing 10 ml of 0.1 M HCl and 40 ml of 0.2 M H_(2)SO_(4)

What will be the pH of a solution formed by mixing 40 ml of 0.10 M HCl with 10 ml of 0.45 M NaOH ?

Calculate the pH of resulting solution obtained by mixing 50 mL of 0.6N HCl and 50 ml of 0.3 N NaOH

The pH of a solution obtained by mixing 50 mL of 2N HCI and 50 mL of 1 N NaOH is [log 5 = 0.7]

Calculate the pH of a solution which contains 100mL of 0.1 M HC1 and 9.9 mL of 1.0 M NaOH .

The normality of solution obtained by mixing 100 ml of 0.2 M H_(2) SO_(4) with 100 ml of 0.2 M NaOH is

The nature of mixture obtained by mixing 50mL of 0.1M H_(2)SO_(4) and 50mL of 0.1M NaOh is:

The resulting solution obtained by mixing 100 ml 0.1 m H_2SO_4 and 50 ml 0.4 M NaOH will be