The solubility of CsBr(3) (MW = 373) i...

The solubility of `CsBr_(3)` (MW = 373) in water is 746 ppm . The solubility product of `CsBr_(3)` is , therefore

A

`1.6 xx10^(-11)M^(4)`

B

`4xx10^(-6)M^(2)`

C

`8 xx10^(-9)M^(3)`

D

`3.2 xx10^(14)M^(5)`

AI Generated Solution

Similar Questions

Explore conceptually related problems

Define solubility product.

The solubility of Ca_(3)(PO_(4))_(2) in water is y moles // litre. Its solubility product is

The molar solubility of PbI_(2) in 0.2M Pb(NO_(3))_(2) solution in terms of solubility product, K_(sp)

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-5) mol/letre at 298K. What will be its solubility product ?

The solubility of a springly soluble salt AB_(2) in water is 1.0xx10^(-5) mol L^(-1) . Its solubility product is:

The solubility of AgCl in water at 298 K is 1.06xx10^(-5) mle per litre. Calculate its solubility product at this temperature.

The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-8) mol/litre at 298 K. What will be its solubility product:

The solubility product of BaCl_(2) is 3.2xx10^(-9) . What will be solubility in mol L^(-1)

Solubility if M_(2)S type salt is 3.5xx10^(-6) , then find out its solubility product

The solubility of AgCl in water at 298 K is 1.06xx10^(-5) mole per litre. Calculate its solubility product at this temperature.