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10 gm of helium at 127^(@) C is expanded...

10 gm of helium at `127^(@)` C is expanded isothermally from 100 atm to 1 atm. Calculate the work done when the expansion is carried out (i) in single step, (ii) In three steps, the intermediate pressure being 60 and 30 atm respectively and (iii) reversibly.

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To solve the problem of calculating the work done during the isothermal expansion of helium gas, we will break it down into three parts as specified in the question. ### Given Data: - Mass of helium (He) = 10 g - Molar mass of helium = 4 g/mol - Temperature (T) = 127 °C = 400 K (since T(K) = T(°C) + 273) - Initial pressure (P1) = 100 atm - Final pressure (P2) = 1 atm ...
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