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Calculate the standard entropy change fo...

Calculate the standard entropy change for the reaction `X hArr Y` if the value of `DeltaH^@ = 28.40 kJ` and equilibirum constant is `1.8 xx 10^(-7)` at 298 K.

Text Solution

Verified by Experts

We know that,
`DeltaG^(@) = -2.303 RT log K`
`=-2.303 xx 8.314 xx 298 xx log 1.8 xx 10^(-7)`
`=38.498` kJ mol.
Also, `DeltaG^(@) = DeltaH^(@) - TDeltaS^(@)`
`therefore DeltaS^(@) = (DeltaH^(@) - DeltaG^(@))/T`
`=(28.40 - 38.498)/298`
`=-33.8 JK^(-1) mol^(-1)`
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