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Calculate the temperature, at which the ...

Calculate the temperature, at which the reaction given below is at equilibrium,
`Ag_(2)O(s) to 1/2 O_(2)(g)`
Given, `DeltaH = 30.5 kJ mol^(-1)` and `DeltaS = 0.066 kJK^(-1)"mol"^(-1)`

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AI Generated Solution

To calculate the temperature at which the reaction \( \text{Ag}_2\text{O}(s) \rightleftharpoons \frac{1}{2} \text{O}_2(g) \) is at equilibrium, we can use the Gibbs free energy equation: \[ \Delta G = \Delta H - T \Delta S \] At equilibrium, the Gibbs free energy change (\( \Delta G \)) is zero. Therefore, we can set up the equation as follows: ...
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