Home
Class 12
CHEMISTRY
Calculate the heat of neutralization by ...

Calculate the heat of neutralization by mixing `200mL` of `0.1 MH_(2)SO_(4)` and `200mL ` of `0.2 MKOH `if heat generated by the mixing is `2.3 kJ`.

Text Solution

AI Generated Solution

To calculate the heat of neutralization for the reaction between sulfuric acid (H₂SO₄) and potassium hydroxide (KOH), we can follow these steps: ### Step-by-Step Solution: 1. **Determine the number of equivalents of H₂SO₄:** - The formula for calculating equivalents is: \[ \text{Equivalents} = \text{Volume (L)} \times \text{Molarity (mol/L)} \times \text{n} ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The nature of mixture obtained by mixing 50mL of 0.1M H_(2)SO_(4) and 50mL of 0.1M NaOh is:

The normality of solution obtained by mixing 100 ml of 0.2 M H_(2) SO_(4) with 100 ml of 0.2 M NaOH is

The normality of solution obtained by mixing 100 ml of 0.2 M H_(2) SO_(4) with 100 ml of 0.2 M NaOH is

Calculate the pH of solution obtained by mixing 10 ml of 0.1 M HCl and 40 ml of 0.2 M H_(2)SO_(4)

The weight of solute present in 200mL of 0.1M H_(2)SO_(4) :

Calculate the normality of a solution obtained by mixing 100 mL of 0.2 N KOH and 100 mL of 0.1 MH_(2)SO_(4) .

Calculate the normality of a solution obtained by mixing 200 mL of 1.0 N NaOH and 100 mL of pure water.

The pH of a solution obtained by mixing 50 mL of 0.4 N HCl and 50 mL of 0.2 N NaOH is

Calculate the heat of neutralisation from the following data: 200mL of 1M HCI is mixed with 400mL of 0.5M NaOH . The temperature rise in calorimeter was found to be 4.4^(@)C . Water equivalent of calorimeter is 12g and specific heat is 1cal mL^(-1) degree^(-1) for solution.

Calculate the heat of neutralisation from the following data: 200mL of 1M HCI is mixed with 400mL of 0.5M NaOH . The temperature rise in calorimeter was found to be 4.4^(@)C . Water equivalent of calorimeter is 12g and specific heat is 1cal mL^(-1) degree^(-1) for solution.