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Greenhouse gas CO(2) can be converted to...

Greenhouse gas `CO_(2)` can be converted to `CO(g)` by the following reaction
`CO_(2)(g)+H_(2)(g) rarr CO_(2)+H_(2)O(g)` , termed as water gas reaction.
Calculate `DeltaH` at 1400 K using the given data for 1000K , assuming the `C_(p)^(@)` values remain constant in the given temoerature range.
`DeltaH=35040 J"mol"^(-1), C_(p)^(@)(CO_(2))=(42.31 + 10.09 xx 1^(-3)T) J "mol"^(-1)K_(1)`
`C_(P)^(@)(H_(2))=(27.40 + 3.20 xx 10^(-3)T) J"mol"^(-1)K_(1)`
`C_(P)^(@)(CO)=(28.34+ 4.14 xx 10^(-3)T)J"mol"^(-1)K^(-1)`
`C_(P)^(@)(H_(2)O)=(30.09 + 10.67 xx 10^(-3)T)J"mol^(-1)K^(-1)`

Text Solution

Verified by Experts

`DeltaH_(1273 K)^(@) = DeltaH_(298 K)^(@) + int_(298 K)^(1273 K) {(DeltaC_(p))dT}`
where, `DeltaCO_(P) = C_(P)^(@)(HCl,g) -1/2C_(P)^(@)(H_(2),g) -1/2C_(P)^(@)(Cl_(2),g)`
`=(28.1359 - 1/2 xx 29.0284 - 1/2 xx 31.6556) + (1.8078 + 1/2 xx 0.8355 - 1/2 xx 10.134) xx 10^(-3) T + (1.5453 - 1/2 xx 2.0097 + 1/2 xx 4.0337) xx 10^(-6) T^(2)`
Hence, `DeltaH_(1273 K)^(@) =[-92.236 xx 10^(2) + (-2.2061) -(2.8415 xx 10^(-3))(1273^(3)/3 - 298^(3)/3)] J"mol"^(-1)`
`=-92236 - 2151.0 + 2176.2 + 1736.0 = -94827 J "mol"^(-1) = -94.827 kJ "mol"^(-1)`
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