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The polymerization of ethylene to linear...

The polymerization of ethylene to linear polyethylene is represented by the reaction, `n[CH_(2) = CH_(2)] rarr [-CH_2 - CH_2]`- where, n has large integral value. Given that the average enthalpies of bond dissociation for `C = C and C - C` at 298 K are +590 and +311 kJ/mol respectively, calculate the enthalpy of polymerization per mole of ethylene at 298 K.

Text Solution

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`nCH_(2) = CH_(2) to (-CH_(2) - CH_(2)-)_(n), DeltaH=?`
Thus .n. double bonds are dissociated to form a molecule with 2n single bonds. `DeltaH` for polymerisation of one mole of ethylene.
= Bond energy data for dissociation of bond + Bond energy data for formation of bond.
`DeltaH = (n//n)[e_(C-C)]-(2n//n)[e_(C-C)]`
`=+590 -2 xx 331 = -72 kJ mol^(-1)`
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