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If an endothermic reaction is non-sponta...

If an endothermic reaction is non-spontaneous at freezing point of water becomes feasible at its boiling point then

A

`DeltaH` is negative and `DeltaS` is +ve

B

`DeltaH` and `DeltaS` both are +ve

C

`DeltaH` and `DeltaS` both are `-ve`

D

`DeltaH` is positive and `DeltaS` is negative.

Text Solution

Verified by Experts

The correct Answer is:
B
For endothermic reaction,
`DeltaH = +ve.DeltaG = DeltaH-TDeltaS`
`DeltaG` is +ve at low temperature if `DeltaS` is `+ve` but `T.DeltaS lt DeltaH`. At high temperature, `TDeltaS gt DeltaH` and `DeltaG` becomes negative.
Hence, (B) is the correct option.
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