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For the process H(2)O(l) (1 "bar", 373 K...

For the process `H_(2)O(l) (1 "bar", 373 K) rarr H_(2)O(g) (1"bar", 373 K)` the correct set of thermodynamic parameters is

A

`DeltaS = 0, DeltaS = +ve`

B

`DeltaG =0,DeltaS=-ve`

C

`DeltaG =+ve, DeltaS=0`

D

`DeltaG=-ve, DeltaS=+ve`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(1 bar 373 K)(H_(2)O(l)) At `100^(@), H_(2)O(l)` has equilibrium with `H_(2)O(g)` therefore `DeltaG=0`.
Because liquid molecular are converting into gases molecules therefore `DeltaS = +ve`
Hence, (A) is the correct answer.
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