Two liquids A and B form ideal solutions...

Two liquids A and B form ideal solutions. At 300 K, the vapour pressure of a solution containing 1 mole of A and 3 moles of B is 550 mm Hg . At the same temperature , if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg. The vapour pressures of A and B in their pure states are respectively

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Let us assume the pressure of pure X is `P^(@)`, and that of pure Y is `P_(gamma)^(@)`.
1st case
Mole fraction of `x=(3)/(4)=0.75`
Mole fraction of `t=0.25`
`P_(I)=xP_(x)^(@)+yP_(y)^(@)`
`550=0.75P_(x)^(@)+0.25P_(y)^(@)" "...(1)`
II case
`x=(4)/(5)=0.8, y=0.2`
`P_(r)=xP_(X)^(0)+yP_(y)^(x)`
`=560=0.8P_(x)^(@)+0.2P_(y)^(@) " "....(2)`
From Eqas. (1) and (2) we get
`rArr P_(x)^(@)=660 mm Hg`
`P_(y)^(0)=400 mm Hg`

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