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What will be the boliling point of bromi...

What will be the boliling point of bromine when `174.5 mg` of octa-atomic sulphur is added to `78 g` of bromine? `k'_(b)` for `Br_(2)` is `5.2 Kmol^(-1) kg` and `b.pt.` of `Br_(2) " is " 332.15 K`

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To find the boiling point of bromine when 174.5 mg of octa-atomic sulfur is added to 78 g of bromine, we will follow these steps: ### Step 1: Convert the mass of sulfur from mg to g Given mass of sulfur = 174.5 mg To convert mg to g: \[ \text{Mass of sulfur in grams} = \frac{174.5 \text{ mg}}{1000} = 0.1745 \text{ g} ...
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