A certain solution of benzoic acid in benzene boil at `82.6^(@)C` and freezes at `3.1^(@)C`. What information about the no of particiles and the structure of benzoic acid at the two temperature can be deduced from the above data ? The boiling point and freezing point of pure benzene are `180.1^(@)C and 5.5^(@)C` respectively.
`K_(r)=5.12 k kg//"mol", k_(b)=2.67 k` kg/ mol.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the elevation in boiling point (ΔT_b)
The boiling point of the solution is given as 82.6°C, and the boiling point of pure benzene is 80.1°C.

\[ \Delta T_b = T_{solution} - T_{pure} = 82.6°C - 80.1°C = 2.5°C \]
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