Home
Class 12
CHEMISTRY
The vapour pressure of pure components A...

The vapour pressure of pure components A and B are 200 torr and 160 torr respectively. The total pressure of the solutions obtained by mixing 2 moles of A and 3 B moles of B is.....

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of two pure liquids (A) and (B) are 100 and 80 torr respectively. The total pressure of solution obtained by mixing 2 mole of (A) and 3 mole of (B) would be :-

The vapour preesure of two pure liquids A and B are 5 and 10 torr respectively. Calculate the total pressure of the solution (in torr) obtained by mixing 2 mole of A and 3 mole of B.

The vapour pressure of two liquids 'P' and 'Q' are 80 and 60 torr respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mol of Q would be

The vapour pressure of two liquids 'P' and 'Q' are 80 and 60 torr respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mol of Q would be

A solution at 20^(@)C is composed of 1.5 mol of benzene and 3.5 mol of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are 74.7 torr and 22.3 torr, respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively:

The vapour pressure of two pure liquids A and B are 50 and 40 torr respectively. If 8 moles of A is mixed with x moles of B , then vapour pressure of solution obtained is 48 torr. What is the value of x.

The vapour pressures of pure liquid A and pure liquid B at 20^(@)C are 22 and 75 mm of Hg respectively. A solution is prepared by mixing equal moles of A and B. Assuming the solution to be ideal, calculate the vapour pressure of the solution.

The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is:

Benzene and toluene form nearly ideal solution. At 298 K , the vapour pressure of pure benzene is 150 torr and of pure toluence is 50 torr. Calculate the vapour pressure of the solution, containing equal weights of two substances at this temperature?

The vapour pressure of two pure liquids A and B are 200 and 400 tor respectively at 300K. A liquid solution (ideal) of A and B for which the mole fraction of A is 0.40 is contained in a cylinder. The composition of components A and B in vapour phase after equilibrium is reached between vapour & liquid phase, respectively is