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0.5N solution of a salt placed between t...

0.5N solution of a salt placed between two Pt electrodes 2.0 cm apart and having area of cross-section 2.5 `cm^(2)` has resistance of 25 ohms. Calculate the conductance and cell constant.

Text Solution

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Specific conductance (k)=Conductance `xx " Cell constant"`
`=1/R xx (l/a) =1/(25) xx (2/4) =0.02 "ohm"^(-1) cm^(-1)`
`wedge_(c)=("specific conductance" xx 1000)/("C (equiv "L^(-1)))=(0.02 xx 1000)/(0.5) =40" ohm"^(-1) cm^(2) eq^(-1)`
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