Home
Class 12
CHEMISTRY
The equilibrium constant of the reaction...

The equilibrium constant of the reaction :
`Cu(s)+2Ag^(+)(aq) to Cu^(2+)(aq) +2Ag(s),E^(@)=0.46V` at 298 K is :

A

`2.0 xx 10^(10)`

B

`4.0 xx 10^(10)`

C

`4.0 xx 10^(15)`

D

`2.4 xx 10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
C

`K="antilog "[(nE^(@))/(0.059)]="antilog" [(2 xx 0.46)/(0.059)]`
=antilog 15.593
`=3.9 xx 10^(15)`
`approx 4 xx 10^(15)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The equivalent constant of the reaction: Cu(s)+2Ag^(+)(aq.) rarr Cu^(2+)(aq.)+2Ag(s) E^(@)=0.46 V at 298 K ,is:

The equilibrium constant of the reaction : Zn(s)+2Ag^(+)(aq)toZn(aq)+2Ag(s),E^(@)=1.50V at 298 K is

The equilibrium constant of the reaction; Cu(s)+2Ag + (aq)⟶Cu 2+ (aq)+2Ag(s) E o =0.46V at 298K

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V

Given the equilibrium constant : K_(c) of the reaction : Cu(s) + 2Ag^(+)(aq) rightarrow Cu^(2+) (Aq) + 2Ag(s) is 10xx10^(15) , calculate the E_(cell)^(@) of this reaction at 298K . ([2.303 (RT)/(Ft) at 298K = 0.059V])

The equilibrium constant for the reactions Cu (s)+ 2Ag^(+) aq hArr Cu^(2+) (aq) +2Ag(s) is 2.0 xx 10 ^(15) " at " 278 K. Find the equilibrium concentration of Cu^(2+) (aq) if that of Ag^(+) (aq) is 1.0 xx 10 ^(-11) " mol " L^(-1)

The equilibrium constant for a cell reaction, Cu(g) + 2Ag^+(aq) → Cu^(2+)(aq) + 2Ag (s) is 4 × 10^16 . Find E° (cell) for the cell reaction.

The equilibrium constant at 298 K for the reaction Cu(s) + 2Ag+ (aq) ⇌ Cu2+ (aq) + 2Ag(s) is 2.0 × 1015 . The concentrations of Cu2+ and Ag+ ions are 1.8 × 10-2 mol L-1 and 3.0 x 10-19 mol L-1 respectively. Is this reaction at equilibrium?

Using the standerd half-cell potential listed, calculate the equilibrium constant for the reaction : Co(s)+2H^(+)(aq)toCo^(2+)(aq)+H_(2)(g)" at 298 K" Co^(2+)(aq)+2e^(-)toCo(s) E^(@)=-0.277 V