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K(d) for dissociation of [Ag(NH(3))(2)]^...

`K_(d)` for dissociation of `[Ag(NH_(3))_(2)]^(+)` into `Ag^(+)` and `NH_(3)` is `6 xx 10^(-8)`. Calculae `E^(@)` for the following half reaction.
`AG(NH_(3))_(2)^(+) +e^(-) rarr Ag +2NH_(3)`
Given `Ag^(+) +e^(-) rarr Ag, E^(@) = 0.799V`

A

0.372

B

0.799

C

0.7781

D

0.6

Text Solution

Verified by Experts

The correct Answer is:
A
`Ag^(+)+e^(-) to Ag, E^(@)=0.799, triangleG^@=-7.71 xx 10^(4)J`
`Ag(NH_(3))_(2)^(+) to Ag^(+) +2NH_(3), K=6 xx 10^(-8), triangleG^(@)=(-2.303 RT)log K=4.12xx 10^(4)J`
`triangleG_("net")^(@)=(-7.71 xx 10^(4)J)+(4.12 xx 10^(4)J)=-3.59 xx 10^(4)J`
`E^(@)=(-triangleG^(@))/(nF)=0.372V`
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