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The solution of CuSO(4) in which copper ...

The solution of `CuSO_(4)` in which copper rod is immersed is diluted to 10 times. The reduction electrode potential

A

Increase by 0.030 V

B

Decreasse by 0.030V

C

Increase by 0.059 V

D

Decrease by 0.059 V

Text Solution

Verified by Experts

The correct Answer is:
B

`Cu^(2+) +2e to Cu`
`E_(1)=E_(1)^(9) -(0.0591)/(2) log (1)/(Cu^(2+))_(1)`
`E_(2)=E_(1)^(@)-(0.0591)/(2) log (1)/(Cu^(2+))_(2)`
`E_(2)=E_(1)^(@)-(0.0591)/(2) log (10)/((Cu_(1)^(2+))`
`=E_(1)^(@)-(0.0591)/(2) log (1)/((Cu_(1)^(2+))-(0.0591)/(2) log 10`
`=E_(1)-0.030V`
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