Home
Class 12
CHEMISTRY
As dillution takes place...

As dillution takes place

A

oxidation potential decreases

B

reduction potential increases

C

oxidation potential increases

D

cell potential may increases

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the effects of dilution on electrode potentials, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Nernst Equation**: The Nernst equation relates the electrode potential to the concentrations of the reactants and products. For a reduction reaction, it is given by: \[ E = E^0 - \frac{2.303}{nF} \log \left( \frac{[Ox]}{[Red]} \right) \] where \(E^0\) is the standard electrode potential, \(n\) is the number of electrons transferred, \(F\) is Faraday's constant, \([Ox]\) is the concentration of the oxidized form, and \([Red]\) is the concentration of the reduced form. 2. **Identifying the Reaction**: In this case, we are looking at the reduction of Mn²⁺ to Mn. Therefore, we can rewrite the Nernst equation specifically for this reaction: \[ E_{Mn^{2+}/Mn} = E^0_{Mn^{2+}/Mn} - \frac{2.303}{nF} \log \left( \frac{[Mn]}{[Mn^{2+}]} \right) \] 3. **Analyzing the Effect of Dilution**: As dilution occurs, the concentration of Mn²⁺ (the oxidized form) decreases. This affects the logarithmic term in the Nernst equation: \[ E_{Mn^{2+}/Mn} = E^0_{Mn^{2+}/Mn} - \frac{2.303}{nF} \log \left( \frac{[Mn]}{[Mn^{2+}]} \right) \] - If \([Mn^{2+}]\) decreases (due to dilution), the term \(\log \left( \frac{[Mn]}{[Mn^{2+}]} \right)\) will become less negative (or more positive), leading to a decrease in the overall electrode potential \(E\). 4. **Conclusion on Reduction Potential**: Therefore, as dilution increases, the reduction potential \(E_{Mn^{2+}/Mn}\) decreases. 5. **Considering Oxidation Potential**: The oxidation potential can be derived similarly: \[ E_{Mn/Mn^{2+}} = E^0_{Mn/Mn^{2+}} - \frac{2.303}{nF} \log \left( \frac{[Mn^{2+}]}{[Mn]} \right) \] - As dilution increases, \([Mn^{2+}]\) decreases, which means that the logarithmic term becomes less negative (or more positive), leading to an increase in the oxidation potential \(E_{Mn/Mn^{2+}}\). ### Summary of Effects: - **Reduction Potential**: Decreases with dilution. - **Oxidation Potential**: Increases with dilution.

To solve the question regarding the effects of dilution on electrode potentials, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Nernst Equation**: The Nernst equation relates the electrode potential to the concentrations of the reactants and products. For a reduction reaction, it is given by: \[ E = E^0 - \frac{2.303}{nF} \log \left( \frac{[Ox]}{[Red]} \right) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

In sponges digestion takes place in

No digestion takes place in the

Maximum digestion takes place in ?

Most of digestion takes place in

Carbon assimilation takes place in

In Pinus the fertilisation takes place in the

Micelles formation takes place

The process of guttation takes place