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Given that, Ni^(2+)//Ni=0.25 V, Cu^(2+...

Given that,
`Ni^(2+)//Ni=0.25 V, Cu^(2+)//Cu=0.34 V`,
`Ag^(+)//Ag=0.80 V` and `Zn^(2+)//Zn=-0.76 V`
Which of the following reaction under standard condition will not take place in the specified direction ?

A

`Ni^(2+) (aq.)+Cu(s) to Ni(s)+Cu^(2+)(aq.)`

B

`Cu(s)+2Ag^(+)(aq.) to Cu^(2+) (aq.) +2Ag(s)`

C

`Cu(s)+2H^(+) (aq.) to Cu^(2+) (aq.) +H_(2)(g)`

D

`Zn(s)+2H^(+). (aq.) to Zn^(2+) (aq.) +3H_(2)(g)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which reactions will not take place in the specified direction under standard conditions, we will analyze the given half-reactions and their standard reduction potentials. ### Given Data: - \( \text{Ni}^{2+} + 2e^- \rightarrow \text{Ni} \) \( E^\circ = 0.25 \, \text{V} \) - \( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \) \( E^\circ = 0.34 \, \text{V} \) - \( \text{Ag}^+ + e^- \rightarrow \text{Ag} \) \( E^\circ = 0.80 \, \text{V} \) - \( \text{Zn}^{2+} + 2e^- \rightarrow \text{Zn} \) \( E^\circ = -0.76 \, \text{V} \) ### Analyzing Each Reaction: 1. **Reaction A:** \[ \text{Ni}^{2+} + \text{Cu} \rightarrow \text{Ni} + \text{Cu}^{2+} \] - Here, Ni is trying to displace Cu. - Since \( E^\circ_{\text{Cu}} (0.34 \, \text{V}) > E^\circ_{\text{Ni}} (0.25 \, \text{V}) \), Cu cannot be displaced by Ni. - **Conclusion:** This reaction will not take place. 2. **Reaction B:** \[ \text{Cu} + 2\text{Ag}^+ \rightarrow \text{Cu}^{2+} + 2\text{Ag} \] - Here, Ag is trying to displace Cu. - Since \( E^\circ_{\text{Ag}} (0.80 \, \text{V}) > E^\circ_{\text{Cu}} (0.34 \, \text{V}) \), Ag can displace Cu. - **Conclusion:** This reaction will take place. 3. **Reaction C:** \[ \text{Cu} + 2\text{H}^+ \rightarrow \text{Cu}^{2+} + \text{H}_2 \] - Here, Cu is trying to displace H. - Since \( E^\circ_{\text{H}^+} (0.00 \, \text{V}) > E^\circ_{\text{Cu}} (0.34 \, \text{V}) \), Cu cannot displace H. - **Conclusion:** This reaction will not take place. 4. **Reaction D:** \[ \text{Zn} + 2\text{H}^+ \rightarrow \text{Zn}^{2+} + \text{H}_2 \] - Here, Zn is trying to displace H. - Since \( E^\circ_{\text{Zn}} (-0.76 \, \text{V}) < E^\circ_{\text{H}^+} (0.00 \, \text{V}) \), Zn can displace H. - **Conclusion:** This reaction will take place. ### Summary of Results: - **Reactions that will not take place:** A and C. - **Reactions that will take place:** B and D. ### Final Answer: The reactions that will not take place in the specified direction are **Reaction A** and **Reaction C**.
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