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The cell potential for the unbalanced ch...

The cell potential for the unbalanced chemical reaction:
`Hg_(2)^(2+)+NO_(3)^(-)+H_(3)O^(+) to Hg^(2+) +HNO_(2)+H_(2)O+e^(-)`

Is measured under standard conditions in the electrochemical sell shown in the diagram were
Equilibrium constant for cell reaction is :

A

`10^(3//2)`

B

`e^(3/2)`

C

`e^(-2/3)`

D

`10^(2/3)`

Text Solution

Verified by Experts

The correct Answer is:
D

`E^(@)-(0.0591)/(n) log K_(c)`
`log K_(c)=(2 xx 0.02)/(0.06) =2/3`
`=10^(2/3)`
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