Given that `E_(Cu^(2+)//Cu)^(0)=0.337` and `E_(Cu^(+)//Cu^(2+))^(0)=-0.153V`. then calculate `E_(Cu^(+)//Cu)^(0)`

Given that E_(cu^(+2)//cu)^(@)=+0.34 V E_(Mg^(+2)//Mg)^(@)=-2.37V which of the following correct

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@) =0.43V E_(Cu^(+)//Cu)^(@)=0.55V E_(Cu^(2+)//Cu^(+))^(@) =

If E_(Cu^(2+)|Cu)^(@) = 0.34V and E_(Cu^(2+)|Cu^(+))^(@)= 0.15 V then the value for disproportion for Cu^(+) is :

Given E_(Ag^(+)//Ag)^(@)=+0.80 V, E_(Cu^(2+)//Cu)^(@)=+0.34 V, E_(Fe^(3+)//Fe^(2+))^(@)=+0.76 V, E_(Ce^(4+)//Ce^(3+))^(@)=+1.60 V Which of the following statements is not correct ?

Four different solution containing 1M each of Au^(+3), Cu^(+2), Ag^(+), Li^(+) are being electrolysed by using inert electrodes. In how many samples, metal ions would be deposited at cathode? ["Given :" E_(Ag^+//Ag)^(0) = 0.8, E_(Au^(+3)//Au)^(0) = 1.00 V E_(Cu^(+2)//Cu)^(0) = 0.34 V, E_(Li^(+)//Li)^(0)= -3.03 V ]

Cu^(+) ion is not stable in aqueous solution because because of dispropotionation reaction. E^(@) value of disproportionation of Cu^(+) is [E_(Cu^(2+)//Cu^(+))^(@)=+ 0.15 V, E_(Cu^(2+)//Cu)^(@)=0.34 V]

Find the equilibrium constant for the reaction Cu^(2+)+ 1n^(2+) Cu^(+) + 1n^(3+) Given that E_(CU^(2+)//CU^(+))^(@) = 0.15V, E_(In^(2+)//1n^(+)) = -0.4V E_(1n^(3+)//1n^(+))^(@) = - 0.42V