Home
Class 12
CHEMISTRY
The emf of the cell reaction Zn(s) +Cu...

The emf of the cell reaction
`Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s)`
is `1.1V`. Calculate the free enegry change for the reaction. If the enthalpy of the reaction is `-216.7 kJ mol^(-1)`, calculate the entropy change for the reaction.

Text Solution

Verified by Experts

The correct Answer is:
`-14.76 JK^(-1)mol^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The cell reaction Zn(s) + Cu^(+2)rarr Zn^(+2) + Cu(s) is best represented as :

The standard free energy change for a reaction is -213.3 KJ mol^(-1) "at" 25^(@)C . If the enthalpy change of the reaction is -217.77 KJ "mole"^(-1) . Calculate the magnitude of entropy change for the reaction in Joule "mole"^(-1)

The standard potential of a cell using the reaction is 1.12 . The heat of the reaction is -504.2kJ mol ^(-1) at 25^(@)C . Calculate the entropy change.

Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + Cu(s) The cell representation for the above redox reaction is

In the reaction A^(o+) +B rarr A +B^(o+) , there is no entropy changes. If enthalpy change is 20 kJ of A^(o+) , calculate DeltaG for the reaction.

E^(@) for the cell Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s) is 1.1V at 25^(@)C the equilibrium constant for the cell reaction is about

The equilibrium constant for a cell reaction, Cu(g) + 2Ag^+(aq) → Cu^(2+)(aq) + 2Ag (s) is 4 × 10^16 . Find E° (cell) for the cell reaction.

Calculate the standard free enegry change for the reaction: Zn + Cu^(2+)(aq) rarr Cu+Zn^(2+) (aq), E^(Theta) = 1.20V

The measured e.m.f. at 25^(@)C for the cell reaction, Zn(s) +XCu^(2+)._((eq))(0.1M) rarr Cu(s) ._((aq)) +Zn^(2+)(1.0M) is 1.3 volt, calculate E^(@) for the cell reaction.

The standard emf for the cell reaction, 2Cu^(+)(aq)toCu(s)+Cu^(2+)(aq) is 0.36V at 298K . The equilibrium constant of the reaction is